Informational Site NetworkInformational Site Network
Privacy
 
Home Top Rated Puzzles Most Viewed Puzzles All Puzzle Questions Random Puzzle Question Search


Tilting At The Ring

(PUZZLING TIMES AT SOLVAMHALL CASTLE)

Another favourite sport at the castle was tilting at the ring. A horizontal bar was fixed in a post, and at the end of a hanging supporter was placed a circular ring, as shown in the above illustrated title. By raising or lowering the bar the ring could be adjusted to the proper height—generally about the level of the left eyebrow of the horseman. The object was to ride swiftly some eighty paces and run the lance through the ring, which was easily detached, and remained on the lance as the property of the skilful winner. It was a very difficult feat, and men were not unnaturally proud of the rings they had succeeded in capturing.



At one tournament at the castle Henry de Gournay beat Stephen Malet by six rings. Each had his rings made into a chain—De Gournay's chain being exactly sixteen inches in length, and Malet's six inches. Now, as the rings were all of the same size and made of metal half an inch thick, the little puzzle proposed by Sir Hugh was to discover just how many rings each man had won.








Answer:




"By my halidame!" exclaimed Sir Hugh, "if some of yon varlets had been put in chains, which for their sins they do truly deserve, then would they well know, mayhap, that the length of any chain having like rings is equal to the inner width of a ring multiplied by the number of rings and added to twice the thickness of the iron whereof it is made. It may be shown that the inner width of the rings used in the tilting was one inch and two-thirds thereof, and the number of rings Stephen Malet did win was three, and those that fell to Henry de Gournay would be nine."



The knight was quite correct, for 1-2/3 in. × 3 + 1 in. = 6 in., and 1-2/3 in. x 9 + 1 in. = 16 in. Thus De Gournay beat Malet by six rings. The drawing showing the rings may assist the reader in verifying the answer and help him to see why the inner width of a link multiplied by the number of links and added to twice the thickness of the iron gives the exact length. It will be noticed that every link put on the chain loses a length equal to twice the thickness of the iron.















Random Questions

Three Men In A Boat.
Combination and Group Problems
Buying Apples.
Money Puzzles
The Wizard's Cats.
Various Dissection Puzzles
The Reve's Puzzle
CANTERBURY PUZZLES
Tilting At The Ring
PUZZLING TIMES AT SOLVAMHALL CASTLE
Magic Squares Of Two Degrees.
Magic Squares Problem.
A New Counter Puzzle.
The Guarded Chessboard
The Three Sheep.
Chessboard Problems
The Deified Puzzle.
Unicursal and Route Problems
The Millionaire's Perplexity.
Money Puzzles
Water, Gas, And Electricity.
Unicursal and Route Problems
Another Linoleum Puzzle.
Patchwork Puzzles
The Betsy Ross Puzzle.
Various Dissection Puzzles
The Nun's Puzzle
CANTERBURY PUZZLES
The Thirty-three Pearls.
Money Puzzles